96x-16x^2+256=0

Solution for 96x-16x^2+256=0 equation:

96x-16x^2+256=0

a = -16; b = 96; c = +256;
Δ = b2-4ac
Δ = 962-4·(-16)·256
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-160}{2*-16}=\frac{-256}{-32}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+160}{2*-16}=\frac{64}{-32}
=-2
$